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Solve the system of equations. 2y = -6x - 4 8x = 4y - 32 (4, -2) infinitely many solutions (-2, 4) no solution

Solve the system of equations.
2y = -6x - 4
8x = 4y - 32
(4, -2)
infinitely many solutions
(-2, 4)
no solution

Answer

To solve the system of equations, we first rewrite them in a more standard form:

  1. From the first equation: 2y = -6x - 4 can be rewritten as y = -3x - 2.
  2. From the second equation: 8x = 4y - 32 can be rewritten as 8x = 4(y - 8) or y = 2x + 8.

Now, we have the system:

  1. y = -3x - 2
  2. y = 2x + 8

Set the equations equal to each other:

-3x - 2 = 2x + 8

Solve for x:

  1. Add 3x to both sides: -2 = 5x + 8
  2. Subtract 8 from both sides: -10 = 5x
  3. Divide by 5: x = -2

Substitute x = -2 into one of the original equations to find y:

y = 2(-2) + 8 = -4 + 8 = 4

The solution is (-2, 4).

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